4[2(2x-2)]=2(4-3x)

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Solution for 4[2(2x-2)]=2(4-3x) equation:


Simplifying
4[2(2x + -2)] = 2(4 + -3x)

Reorder the terms:
4[2(-2 + 2x)] = 2(4 + -3x)
4[(-2 * 2 + 2x * 2)] = 2(4 + -3x)
4[(-4 + 4x)] = 2(4 + -3x)
[-4 * 4 + 4x * 4] = 2(4 + -3x)
[-16 + 16x] = 2(4 + -3x)
-16 + 16x = (4 * 2 + -3x * 2)
-16 + 16x = (8 + -6x)

Solving
-16 + 16x = 8 + -6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6x' to each side of the equation.
-16 + 16x + 6x = 8 + -6x + 6x

Combine like terms: 16x + 6x = 22x
-16 + 22x = 8 + -6x + 6x

Combine like terms: -6x + 6x = 0
-16 + 22x = 8 + 0
-16 + 22x = 8

Add '16' to each side of the equation.
-16 + 16 + 22x = 8 + 16

Combine like terms: -16 + 16 = 0
0 + 22x = 8 + 16
22x = 8 + 16

Combine like terms: 8 + 16 = 24
22x = 24

Divide each side by '22'.
x = 1.090909091

Simplifying
x = 1.090909091

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